(1-x)^2=x^2+0,2^2

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Solution for (1-x)^2=x^2+0,2^2 equation: 



(1-x)^2=x^2+0.2^2

We move all terms to the left:

(1-x)^2-(x^2+0.2^2)=0

We add all the numbers together, and all the variables

(-1x+1)^2-(x^2+0.2^2)=0

We get rid of parentheses

-x^2+(-1x+1)^2-0.2^2=0

We add all the numbers together, and all the variables

-1x^2+(-1x+1)^2-0.04=0

We move all terms containing x to the left, all other terms to the right

-1x^2+(-1x+1)^2=0.04

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